Applied Differential Equations I

Mathematics

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- Part I problem 6. The answer should be y=6(t^2)e^(-2t)+e^(-2t).
- Part 1 problem 7b. The answer has an arithmetic mistake. When s=-2, the equation should be 8-6+4=C(-1). This changes the values of the constants to A=3, C=-6, B=-1. Therefore the correct answer is y = 3e^(-t) - e^(-2t) - 6te^(-2t).

Material on Test 1

Test 1 Review Questions

Old Test 1

Old Test 1 Answers

Material on Test 2

Test 2 Review Questions

Old Test 2. On problem 3, ignore the verbiage; just find a particular solution by variation of parameters.

Old Test 2 Answers. The answer to problem 3 is correct; ignore the method.

Material on Test 3

Test 3 Review Questions

Old Test 3 (does not cover all material)

Old Test 3 Answers

Material on the Final Exam

Old Final Exam (does not cover all material)

Answers for Old Final Exam. Corrections:

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