Current Announcements

I have submitted the final course grades
(anonymous sorted list)
to the registrar.
The anonymous sorted grades for the final exam,
Final/sorted_grades.txt.
The anonymous sorted grades for the combined homeworks scaled to 20,
Homework/sorted_grades.txt.

On request, solution to Homework 4, Problem 1:
(b0 + 5*b1 + 25*b2)^2 equiv 94 (mod 125). (*)
Then b0^2 equiv 4 (mod 5), so b0 = 2 or = 3. Take 2.
Then (2 + 5*b1)^2 equiv 94 (mod 25), reducing (*) modulo 25.
So 4 + 4*5*b1 equiv 19 (mod 25), or 20*b1 equiv 15 (mod 25).
That means that 4*b1 equiv 3 (mod 5) [note the division by 5]
or b1 = 2.
Thus (12 + 25*b3)^2 equiv 94 (mod 125) or 144 + 2*12*25*b3 equiv 94 (mod 125).
So 12*50*b2 equiv 9419 equiv 75 (mod 125).
That means 12*2*b2 equiv 3 (mod 5) [note the division by 25]
or b3 = 2.

The final exam is Wednesday, May 5, at 9am in our class room.
You may bring 3 sheets of notes.

The course web sites for
Spring 2009,
Spring 2008,
Spring 2007
and
Spring 2005
contain old homeworks, midsemester exams, and anonymous grade lists.

My office hours are listed on my
schedule.
