MA-305 Bonus Homework 7

Due at noon, Friday, December 5, 1997
Extended to 1:00pm, Monday, December 8, 1997



You may do the calculations necessary for these problems either by hand or with Maple. Please submit a handwritten solution, or email an ASCII/Postscript/html document to the TA. (You may also submit through email which attached your Maple worksheet.)

  1. Use QR factorization to find the least square fit of problem 4 in Homework 6.

    Solution:

    C(n) = 1.387891671 x ln( x ) - 0.955521423 x + 0.56617708.
    Maple worksheet(Maple text)

  2. *Which of the following are linear transformations?

    Solution:

    (a) Yes.
    (b) No.


    (c) No.
      L(1, 1, 1) + L(1, 1, 1) = (12 + 1, 1 - 1) + (12 + 1, 1 - 1) = ( 2, 0)
      not equivalent to L(1 + 1, 1 + 1, 1 + 1)= L(2, 2, 2) = (22 + 2, 2 - 2) = (6, 0).

  3. **For the given matrix:

    [ 5 0-4 ]
    [ 0-3 0 ]
    [-4 0-1 ]

    Solution:

    (a) - ( lambda - 7) ( lambda + 3 )2.
    (b) 7, -3.
    (c) {(-2, 0, 1)} when lambda = 7 ; {(1, 0, 2), (0, 1, 0)} when lambda =-3.

  4. Which of the following are inner products? For those that are, decide the norm defined in the corresponding inner product.

    Solution:

    (a) Yes. || (x, y, z) || = ( x2 + 2y2 + 3z2 )1/2.
    (b) No. When vT = [ 1, 21/2, -1 ] != 0, < v, v >b = 0.

  5. [ 1 2 1 0 ]
    A = [ 2 3 4 7 ] . Let LA(v) = v. Find:
    [ 3 5 5 7 ]
    [ 3 4 7 14 ]

    Solution:

    (a) The null space of A, the vector space spanned by {(-5, 2, 1, 0), (-14, 7, 0, 1)}.
    (b) The column space of A, Span([1, 2, 3, 3]T, [2, 3, 5, 4]T, [1, 4, 5, 7]T, [0, 7, 7, 14]T).

  6. (Not covered)**Determine if the given matrix is diagonalizable. If so, diagonalize the matrix:

  7. **(a) Find the general solution to the system of differential equations.
    (b) Find the particular solution satisfies the given initial conditions.

    Solution:

    (a) The general solution:


      [ 1 ]
      [3/2]
      C1 [-2] e-5t + C2[ 1] e3t
    (b) The particular solution satisfies the given initial condition:
      u = (7/8)*e-5t + (33/8)*e3t
      v = (11/4)*e3t - (7/4)*e-5t


*: problem from ``Introductory Linear Algebra with Applications'' by Kolman and Hill
**: problem from ``Elmentary Linear Algebra with Applications'' by Hill